Volconvo Debate Forums - View Single Post

rcne · Oct 21, 2004, 10:14 am

0=(0)={(0})=[{(0)}]=()={()}=[{()}]. I see your point but, isn't that just stating equivalence?

Your ordering of the set theory is just n-1 isn't It?

Well maybe I'm off an a tangent, but I don't see the newness of it.

Oct 21, 2004, 10:14 am	#2 (permalink) (top)
rcne Moderator/nobody Posts: 1,566	0=(0)={(0})=[{(0)}]=()={()}=[{()}]. I see your point but, isn't that just stating equivalence? Your ordering of the set theory is just n-1 isn't It? Well maybe I'm off an a tangent, but I don't see the newness of it. Live Long and Prosper (Genetics and Capitalism)